Constant pressure process using steam (LearnChemE.com, 5min). 2000 kJ of heat is isobarically added to steam piston/cylinder starting at 0.45MPa with 0.9kg as vapor and 0.1kg as liquid. Compute the final temperature, work, and state of the steam. Once we have our general energy balance defined, we can straigntforwardly reduce it to its simplest applicable form to solve problems. The energy balance is the same regardless of whether the process uses an ideal gas, steam, or some other working fluid. But the method of solving the problem changes quite a bit depending on the working fluid. Hint: "steam" and H2O are the same thing. So "liquid steam" is also known as "water."

Comprehension questions: 1. Describe how you would solve this problem if the H2O was replaced with a monatomic ideal gas (MW=40). Use the same starting pressure and temperature as the steam, but obviously the entire 1.0 kg will be gas, with no liquid. 2. Describe how you would write the energy balance if the cylinder was 5m3 total, open to the atmosphere, and the pressure was suddenly reduced to 1 bar. Assume the piston has a mass of 0.1kg.

Adiabatic, Reversible Compression of an Ideal Gas in a Piston/Cylinder (LearnChemE.com, 5min). The standard formula for an adiabatic, reversible, ideal gas is derived here in the T,V form. You should be able to rearrange the given equation into the usual form: (T2/T1) = (P2/P1)^(R/Cp) to show they are equivalent. (Hint: PV=RT and Cp=Cv+R). The interesting part of this video is during the last 10 seconds. Watch what happens!

Comprehension Questions:

1. My bicycle pump is about 50cm tall and 2.0cm diameter. When I pump it down, the pressure goes to 100psig (after pumping once or twice). What is the temperature of the air that goes into the tire at that point?

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Elliott replied on Permalink

## Constant Pressure Process with Steam

Constant pressure process using steam (LearnChemE.com, 5min). 2000 kJ of heat is isobarically added to steam piston/cylinder starting at 0.45MPa with 0.9kg as vapor and 0.1kg as liquid. Compute the final temperature, work, and state of the steam. Once we have our general energy balance defined, we can straigntforwardly reduce it to its simplest applicable form to solve problems. The energy balance is the same regardless of whether the process uses an ideal gas, steam, or some other working fluid. But the method of solving the problem changes quite a bit depending on the working fluid.

Hint: "steam" and H2O are the same thing. So "liquid steam" is also known as "water."

Comprehension questions:

1. Describe how you would solve this problem if the H2O was replaced with a monatomic ideal gas (MW=40). Use the same starting pressure and temperature as the steam, but obviously the entire 1.0 kg will be gas, with no liquid.

2. Describe how you would write the energy balance if the cylinder was 5m3 total, open to the atmosphere, and the pressure was suddenly reduced to 1 bar. Assume the piston has a mass of 0.1kg.

Elliott replied on Permalink

## Adiabatic, Reversible Compression of an Ideal Gas (Bang!)

Adiabatic, Reversible Compression of an Ideal Gas in a Piston/Cylinder (LearnChemE.com, 5min). The standard formula for an adiabatic, reversible, ideal gas is derived here in the

T,Vform. You should be able to rearrange the given equation into the usual form:(T2/T1) = (P2/P1)^(R/Cp) to show they are equivalent. (Hint: PV=RT and Cp=Cv+R).

The interesting part of this video is during the last 10 seconds. Watch what happens!Comprehension Questions:

1. My bicycle pump is about 50cm tall and 2.0cm diameter. When I pump it down, the pressure goes to 100psig (after pumping once or twice). What is the temperature of the air that goes into the tire at that point?

2. What is the length (cm) remaining in the pump?